(0) Obligation:

Clauses:

sum(X, 0, X).
sum(X, s(Y), s(Z)) :- sum(X, Y, Z).

Query: sum(a,a,g)

(1) PrologToDTProblemTransformerProof (SOUND transformation)

Built DT problem from termination graph DT10.

(2) Obligation:

Triples:

sumA(X1, s(s(X2)), s(s(X3))) :- sumA(X1, X2, X3).
sumA(X1, s(s(X2)), s(s(X3))) :- sumA(X1, X2, X3).

Clauses:

sumcA(X1, 0, X1).
sumcA(X1, s(0), s(X1)).
sumcA(X1, s(s(X2)), s(s(X3))) :- sumcA(X1, X2, X3).
sumcA(X1, s(0), s(X1)).
sumcA(X1, s(s(X2)), s(s(X3))) :- sumcA(X1, X2, X3).

Afs:

sumA(x1, x2, x3)  =  sumA(x3)

(3) TriplesToPiDPProof (SOUND transformation)

We use the technique of [DT09]. With regard to the inferred argument filtering the predicates were used in the following modes:
sumA_in: (f,f,b)
Transforming TRIPLES into the following Term Rewriting System:
Pi DP problem:
The TRS P consists of the following rules:

SUMA_IN_AAG(X1, s(s(X2)), s(s(X3))) → U1_AAG(X1, X2, X3, sumA_in_aag(X1, X2, X3))
SUMA_IN_AAG(X1, s(s(X2)), s(s(X3))) → SUMA_IN_AAG(X1, X2, X3)

R is empty.
The argument filtering Pi contains the following mapping:
sumA_in_aag(x1, x2, x3)  =  sumA_in_aag(x3)
s(x1)  =  s(x1)
SUMA_IN_AAG(x1, x2, x3)  =  SUMA_IN_AAG(x3)
U1_AAG(x1, x2, x3, x4)  =  U1_AAG(x3, x4)

We have to consider all (P,R,Pi)-chains

Infinitary Constructor Rewriting Termination of PiDP implies Termination of TRIPLES

(4) Obligation:

Pi DP problem:
The TRS P consists of the following rules:

SUMA_IN_AAG(X1, s(s(X2)), s(s(X3))) → U1_AAG(X1, X2, X3, sumA_in_aag(X1, X2, X3))
SUMA_IN_AAG(X1, s(s(X2)), s(s(X3))) → SUMA_IN_AAG(X1, X2, X3)

R is empty.
The argument filtering Pi contains the following mapping:
sumA_in_aag(x1, x2, x3)  =  sumA_in_aag(x3)
s(x1)  =  s(x1)
SUMA_IN_AAG(x1, x2, x3)  =  SUMA_IN_AAG(x3)
U1_AAG(x1, x2, x3, x4)  =  U1_AAG(x3, x4)

We have to consider all (P,R,Pi)-chains

(5) DependencyGraphProof (EQUIVALENT transformation)

The approximation of the Dependency Graph [LOPSTR] contains 1 SCC with 1 less node.

(6) Obligation:

Pi DP problem:
The TRS P consists of the following rules:

SUMA_IN_AAG(X1, s(s(X2)), s(s(X3))) → SUMA_IN_AAG(X1, X2, X3)

R is empty.
The argument filtering Pi contains the following mapping:
s(x1)  =  s(x1)
SUMA_IN_AAG(x1, x2, x3)  =  SUMA_IN_AAG(x3)

We have to consider all (P,R,Pi)-chains

(7) PiDPToQDPProof (SOUND transformation)

Transforming (infinitary) constructor rewriting Pi-DP problem [LOPSTR] into ordinary QDP problem [LPAR04] by application of Pi.

(8) Obligation:

Q DP problem:
The TRS P consists of the following rules:

SUMA_IN_AAG(s(s(X3))) → SUMA_IN_AAG(X3)

R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.

(9) QDPSizeChangeProof (EQUIVALENT transformation)

By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem.

From the DPs we obtained the following set of size-change graphs:

  • SUMA_IN_AAG(s(s(X3))) → SUMA_IN_AAG(X3)
    The graph contains the following edges 1 > 1

(10) YES